2x^2-3z^2+12y=0

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Solution for 2x^2-3z^2+12y=0 equation:


Simplifying
2x2 + -3z2 + 12y = 0

Reorder the terms:
2x2 + 12y + -3z2 = 0

Solving
2x2 + 12y + -3z2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-12y' to each side of the equation.
2x2 + 12y + -12y + -3z2 = 0 + -12y

Combine like terms: 12y + -12y = 0
2x2 + 0 + -3z2 = 0 + -12y
2x2 + -3z2 = 0 + -12y
Remove the zero:
2x2 + -3z2 = -12y

Add '3z2' to each side of the equation.
2x2 + -3z2 + 3z2 = -12y + 3z2

Combine like terms: -3z2 + 3z2 = 0
2x2 + 0 = -12y + 3z2
2x2 = -12y + 3z2

Divide each side by '2'.
x2 = -6y + 1.5z2

Simplifying
x2 = -6y + 1.5z2

Reorder the terms:
x2 + 6y + -1.5z2 = -6y + 6y + 1.5z2 + -1.5z2

Combine like terms: -6y + 6y = 0
x2 + 6y + -1.5z2 = 0 + 1.5z2 + -1.5z2
x2 + 6y + -1.5z2 = 1.5z2 + -1.5z2

Combine like terms: 1.5z2 + -1.5z2 = 0.0
x2 + 6y + -1.5z2 = 0.0

The solution to this equation could not be determined.

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